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Arithmetic Sequences tn= t1 + (n-1)d tn= general term t1= first term n= term number d= constant difference Example 1: 5, 8, 11, 14… Since the sequence is going up by 3, the constant difference is 3. d=3 Find the 17th term in the sequence. Find the general formula. tn= t1 + (n-1)d tn= t1 + (n-1)d t17= 5 + (17-1)3 tn= 5 + (n-1)3 t17= 5 + (16)3 tn= 5+ 3n-3 t17= 5 + 48 tn= 2 + 3n t17= 51 Example 2: If the pattern is going down, the constant difference will be negative. -3, -10, -17, -24… Since the sequence is going down by 7, the constant difference is -7. d= -7 Find the 10th term in the sequence. Find the general formula. tn= t1 + (n-1)d tn= t1 + (n-1)d t10= -3 + (10-1)(-7) tn= -3 + (n-1)(-7) t10= -3 + (9)(-7) tn= -3 + -7n +7 t10= -3 + -63 tn= 4 + -7n t10= -66 Geometric Sequences tn= t1 (r)n-1 tn= general term t1= first term r= common ratio n= term number You find the common ratio for geometric sequences by dividing neighboring terms. Example 3: 5, 10, 20, 40… Find r: 10/5= 2 20/10=2 40/20=2 r=2 Notice that if the pattern is getting larger, that the absolute value of r is greater than 1. Example 4: 64, -48, 36, -27… Find r: -48/64= -3/4 36/-48= -3/4 -27/36= -3/4 r=-3/4 Notice that if the pattern switches positive, negative, positive, negative… or negative, positive…, that r is negative. Notice that if the pattern is getting smaller that the absolute value of r is less than one. Example 5: 200, -100, 50, -25… Find r: -100/200= -1/2, 50/-100= -1/2, -25/50= -1/2, r= -1/2 Find the 7th term. Find the general formula tn= t1 (r)n-1 tn= t1 (r)n-1 t7= 200 (-1/2)7-1 tn= 200 (-1/2)n-1 t7= 200 (-1/2)6 t7= 200 (1/64) t7= 50/16 or 3.125
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