| Logarithms |
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Exponents Baseexponent= Answer the base and exponent can be any real number D: all real numbers the answer must be positive R: y: y > 0 Exponent Rules If the bases are the same: To multiply, add the exponents (x4)(x5) = x9 To divide, subtract the exponents y7 / y4 = y3 Power of a power, multiply the exponents (a7)3 = a21 Logarithms logbaseAnswer = Exponent logbaseargument= answer the base and argument have to be positive D: x: x > 0 the answer can be any real number R: all real numbers Log Rules If the bases are the same: Multiplying can be split into adding logbMN = logbM + logbN Adding logs of the same base can be combined into multiplying the arguments logbM + logbN = logbMN Dividing can be split into subtracting logb(M/N) = logbM - logbN Subtracting with the same base can be combined into dividing the arguments logbM - logbN = logb(M/N) Power of a log can be changed to multiplying logbMk = k logbM Multiplying a number times a log can be changed to a power of the log log k logbM = logbMk
Strategies for Solving Log Problems 1) Change from log notation to exponential notation. Example: log27j=2/3 logbaseanswer=exponent 272/3=j 9=j Example: ln x2 = - 2 logbase=eanswer= exponent e-2 = x2 To get x by itself, take the square root of both sides. Since x is squared, there will be two answers, and you need to +/- the left side (e-2)1/2 = (x2)1/2 or - (e-2)1/2 = (x2)1/2 e-1 = x or – e-1 = x x= 1/e or -1/e 2) Use inverse operations Example: log667 6 to what power gives you 6 to the 7th power? 7 Example: 3log38 a log in the exponent with the same base undo each other 8 3) Take the common log of both sides. Example: 53x= 786 log 53x= log 786 a power of a log can be changed to multiplying 3x(log 5)= log 786 divide both sides by log 5 & 3 x= (log 786) plug it into your calculator (log 5) 3
x= 1.380804387 round to whatever the directions say
4) Use the log properties to simplify and solve. Example: log29(x+3) + log2(x-4)=3 if the bases are the same, you can multiply the argumentslog2(x+3)(x-4)=3 change from log to exponential notation logbaseanswer=exponent
23=(x+3)(x-4) use foil & evaluate 23 8=x2 – x – 12 move the 8 over and get a 0 on one side -8 -8 0= x2 – x – 20 factor 0=(x – 5)(x + 4) use the zero product rule x – 5 = 0 x + 4 = 0 get x by itself in each equation x=5 x= -4 check to make sure the original arguments are positive x=5 negative 4 does not work in either original argument 5) Use the change of base formula: logax= logbx logba Example: 3x= 21 change from exponential notation to log notation log321=x change base to either 10 or e log 21 = x new base is 10, plug into calculator log 3 2.7712= x Example: log516 argument of numerator becomes new argument log54 argument of denominator become new base log416 4 to what power makes 16? 2
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